Base | Representation |
---|---|
bin | 110001011100100110… |
… | …011010111110101001 |
3 | 12002001011012011120001 |
4 | 301130212122332221 |
5 | 1332213323332101 |
6 | 40220215103001 |
7 | 3556461420106 |
oct | 613446327651 |
9 | 162034164501 |
10 | 53093183401 |
11 | 20575799575 |
12 | a358971a61 |
13 | 501184c16b |
14 | 27d9471aad |
15 | 15ab1e3901 |
hex | c5c99afa9 |
53093183401 has 8 divisors (see below), whose sum is σ = 53401939200. Its totient is φ = 52785253200.
The previous prime is 53093183393. The next prime is 53093183443. The reversal of 53093183401 is 10438139035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53093183401 - 23 = 53093183393 is a prime.
It is a super-2 number, since 2×530931834012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53093183461) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 77175 + ... + 334876.
It is an arithmetic number, because the mean of its divisors is an integer number (6675242400).
Almost surely, 253093183401 is an apocalyptic number.
It is an amenable number.
53093183401 is a deficient number, since it is larger than the sum of its proper divisors (308755799).
53093183401 is a wasteful number, since it uses less digits than its factorization.
53093183401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 412799.
The product of its (nonzero) digits is 38880, while the sum is 37.
The spelling of 53093183401 in words is "fifty-three billion, ninety-three million, one hundred eighty-three thousand, four hundred one".
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