Base | Representation |
---|---|
bin | 1111011101000100010… |
… | …01101010110011101010 |
3 | 1212202121101212002000120 |
4 | 13232202021222303222 |
5 | 32144442330433114 |
6 | 1043534431144110 |
7 | 53235465415140 |
oct | 7564211526352 |
9 | 1782541762016 |
10 | 531001421034 |
11 | 195218505a17 |
12 | 86ab3375036 |
13 | 3b0c4b29aa6 |
14 | 1b9b4669590 |
15 | dc2c61e5a9 |
hex | 7ba226acea |
531001421034 has 32 divisors (see below), whose sum is σ = 1230812153856. Its totient is φ = 149577864240.
The previous prime is 531001421033. The next prime is 531001421057. The reversal of 531001421034 is 430124100135.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 531001420995 and 531001421013.
It is not an unprimeable number, because it can be changed into a prime (531001421033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 89031462 + ... + 89037425.
It is an arithmetic number, because the mean of its divisors is an integer number (38462879808).
Almost surely, 2531001421034 is an apocalyptic number.
531001421034 is an abundant number, since it is smaller than the sum of its proper divisors (699810732822).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531001421034 is a wasteful number, since it uses less digits than its factorization.
531001421034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 178068970.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 531001421034 its reverse (430124100135), we get a palindrome (961125521169).
The spelling of 531001421034 in words is "five hundred thirty-one billion, one million, four hundred twenty-one thousand, thirty-four".
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