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53100213531 = 317700071177
BaseRepresentation
bin110001011101000001…
…001111010100011011
312002001122102100002020
4301131001033110123
51332222123313111
640221025505523
73556605240111
oct613501172433
9162048370066
1053100213531
11205797603a2
12a35b1a22a3
135013140cc1
1427da381ab1
1515abb31906
hexc5d04f51b

53100213531 has 4 divisors (see below), whose sum is σ = 70800284712. Its totient is φ = 35400142352.

The previous prime is 53100213527. The next prime is 53100213571. The reversal of 53100213531 is 13531200135.

53100213531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53100213531 - 22 = 53100213527 is a prime.

It is a super-2 number, since 2×531002135312 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (53100213571) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8850035586 + ... + 8850035591.

It is an arithmetic number, because the mean of its divisors is an integer number (17700071178).

Almost surely, 253100213531 is an apocalyptic number.

53100213531 is a deficient number, since it is larger than the sum of its proper divisors (17700071181).

53100213531 is a wasteful number, since it uses less digits than its factorization.

53100213531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17700071180.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 53100213531 its reverse (13531200135), we get a palindrome (66631413666).

The spelling of 53100213531 in words is "fifty-three billion, one hundred million, two hundred thirteen thousand, five hundred thirty-one".

Divisors: 1 3 17700071177 53100213531