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53100441204043 = 191278012781173
BaseRepresentation
bin11000001001011011010001…
…11011110111010101001011
320222000100112001021101000011
430010231220323313111023
523424444200422012133
6304534001140252351
714120244302006662
oct1404555073672513
9228010461241004
1053100441204043
1115a12852809002
125b5727a3a10b7
13238247229c79c
14d18109daddd9
156213e71e06cd
hex304b68ef754b

53100441204043 has 4 divisors (see below), whose sum is σ = 53378453985408. Its totient is φ = 52822428422680.

The previous prime is 53100441204029. The next prime is 53100441204047. The reversal of 53100441204043 is 34040214400135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53100441204043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53100441203996 and 53100441204014.

It is not an unprimeable number, because it can be changed into a prime (53100441204047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139006390396 + ... + 139006390777.

It is an arithmetic number, because the mean of its divisors is an integer number (13344613496352).

Almost surely, 253100441204043 is an apocalyptic number.

53100441204043 is a deficient number, since it is larger than the sum of its proper divisors (278012781365).

53100441204043 is a wasteful number, since it uses less digits than its factorization.

53100441204043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278012781364.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 53100441204043 its reverse (34040214400135), we get a palindrome (87140655604178).

The spelling of 53100441204043 in words is "fifty-three trillion, one hundred billion, four hundred forty-one million, two hundred four thousand, forty-three".

Divisors: 1 191 278012781173 53100441204043