Base | Representation |
---|---|
bin | 110001011101000100… |
… | …110010101110111001 |
3 | 12002001201011122211201 |
4 | 301131010302232321 |
5 | 1332222343120032 |
6 | 40221101454201 |
7 | 3556616166604 |
oct | 613504625671 |
9 | 162051148751 |
10 | 53101145017 |
11 | 2057a237218 |
12 | a35b571361 |
13 | 50133a8c8b |
14 | 27da54533b |
15 | 15abc678e7 |
hex | c5d132bb9 |
53101145017 has 4 divisors (see below), whose sum is σ = 53227878480. Its totient is φ = 52974411556.
The previous prime is 53101145003. The next prime is 53101145029. The reversal of 53101145017 is 71054110135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53101145017 - 227 = 52966927289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53101145057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63366103 + ... + 63366940.
It is an arithmetic number, because the mean of its divisors is an integer number (13306969620).
Almost surely, 253101145017 is an apocalyptic number.
It is an amenable number.
53101145017 is a deficient number, since it is larger than the sum of its proper divisors (126733463).
53101145017 is a wasteful number, since it uses less digits than its factorization.
53101145017 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126733462.
The product of its (nonzero) digits is 2100, while the sum is 28.
The spelling of 53101145017 in words is "fifty-three billion, one hundred one million, one hundred forty-five thousand, seventeen".
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