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531052540234 = 2265526270117
BaseRepresentation
bin1111011101001010011…
…00101011000101001010
31212202201222001012101021
413232211030223011022
532200043422241414
61043543454543054
753236656053536
oct7564514530512
91782658035337
10531052540234
11195244350597
1286b08507a8a
133b1025b7738
141b9bb374bc6
15dc31d6ac24
hex7ba532b14a

531052540234 has 4 divisors (see below), whose sum is σ = 796578810354. Its totient is φ = 265526270116.

The previous prime is 531052540231. The next prime is 531052540241. The reversal of 531052540234 is 432045250135.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 401009362009 + 130043178225 = 633253^2 + 360615^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 531052540234.

It is not an unprimeable number, because it can be changed into a prime (531052540231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132763135057 + ... + 132763135060.

Almost surely, 2531052540234 is an apocalyptic number.

531052540234 is a deficient number, since it is larger than the sum of its proper divisors (265526270120).

531052540234 is a wasteful number, since it uses less digits than its factorization.

531052540234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 265526270119.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 531052540234 its reverse (432045250135), we get a palindrome (963097790369).

The spelling of 531052540234 in words is "five hundred thirty-one billion, fifty-two million, five hundred forty thousand, two hundred thirty-four".

Divisors: 1 2 265526270117 531052540234