Base | Representation |
---|---|
bin | 100110101001001001110… |
… | …0100100011101101001001 |
3 | 200210201202120202021102112 |
4 | 1031102103210203231021 |
5 | 1144004020141141131 |
6 | 15143510513312105 |
7 | 1055465622065501 |
oct | 115222344435511 |
9 | 20721676667375 |
10 | 5311055412041 |
11 | 1768451359525 |
12 | 719399865635 |
13 | 2c6aa444c0b2 |
14 | 1450b0ca0a01 |
15 | 9324576802b |
hex | 4d493923b49 |
5311055412041 has 4 divisors (see below), whose sum is σ = 5311151746512. Its totient is φ = 5310959077572.
The previous prime is 5311055412007. The next prime is 5311055412043. The reversal of 5311055412041 is 1402145501135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5311055412041 - 222 = 5311051217737 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5311055411989 and 5311055412007.
It is not an unprimeable number, because it can be changed into a prime (5311055412043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48084491 + ... + 48194816.
It is an arithmetic number, because the mean of its divisors is an integer number (1327787936628).
Almost surely, 25311055412041 is an apocalyptic number.
It is an amenable number.
5311055412041 is a deficient number, since it is larger than the sum of its proper divisors (96334471).
5311055412041 is an equidigital number, since it uses as much as digits as its factorization.
5311055412041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96334470.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 5311055412041 in words is "five trillion, three hundred eleven billion, fifty-five million, four hundred twelve thousand, forty-one".
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