Base | Representation |
---|---|
bin | 100110101001001001110… |
… | …0100100011101101110011 |
3 | 200210201202120202021111002 |
4 | 1031102103210203231303 |
5 | 1144004020141141313 |
6 | 15143510513312215 |
7 | 1055465622065561 |
oct | 115222344435563 |
9 | 20721676667432 |
10 | 5311055412083 |
11 | 1768451359563 |
12 | 71939986566b |
13 | 2c6aa444c115 |
14 | 1450b0ca0a31 |
15 | 93245768058 |
hex | 4d493923b73 |
5311055412083 has 2 divisors, whose sum is σ = 5311055412084. Its totient is φ = 5311055412082.
The previous prime is 5311055412043. The next prime is 5311055412101. The reversal of 5311055412083 is 3802145501135.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5311055412083 - 216 = 5311055346547 is a prime.
It is a super-2 number, since 2×53110554120832 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5311055412043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655527706041 + 2655527706042.
It is an arithmetic number, because the mean of its divisors is an integer number (2655527706042).
Almost surely, 25311055412083 is an apocalyptic number.
5311055412083 is a deficient number, since it is larger than the sum of its proper divisors (1).
5311055412083 is an equidigital number, since it uses as much as digits as its factorization.
5311055412083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 38.
The spelling of 5311055412083 in words is "five trillion, three hundred eleven billion, fifty-five million, four hundred twelve thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •