5311140403 has 4 divisors (see below), whose sum is σ = 5313834288. Its totient is φ = 5308446520.

The previous prime is 5311140383. The next prime is 5311140409. The reversal of 5311140403 is 3040411135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5311140403 - 2⁹ = 5311139891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5311140409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1343983 + ... + 1347928.

It is an arithmetic number, because the mean of its divisors is an integer number (1328458572).

Almost surely, 2^5311140403 is an apocalyptic number.

5311140403 is a deficient number, since it is larger than the sum of its proper divisors (2693885).

5311140403 is a wasteful number, since it uses less digits than its factorization.

5311140403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2693884.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 5311140403 is about 72877.5713302797. The cubic root of 5311140403 is about 1744.7341464650.

Adding to 5311140403 its reverse (3040411135), we get a palindrome (8351551538).

The spelling of 5311140403 in words is "five billion, three hundred eleven million, one hundred forty thousand, four hundred three".