Base | Representation |
---|---|
bin | 1111011101010010101… |
… | …00010111000110110001 |
3 | 1212202220210010001221210 |
4 | 13232221110113012301 |
5 | 32200214121230213 |
6 | 1043554404310333 |
7 | 53241455442033 |
oct | 7565124270661 |
9 | 1782823101853 |
10 | 531121664433 |
11 | 19527a373628 |
12 | 86b276a23a9 |
13 | 3b113a0a729 |
14 | 1b9c6609c53 |
15 | dc37e720c3 |
hex | 7ba95171b1 |
531121664433 has 32 divisors (see below), whose sum is σ = 760600938240. Its totient is φ = 328463493120.
The previous prime is 531121664429. The next prime is 531121664443. The reversal of 531121664433 is 334466121135.
It is not a de Polignac number, because 531121664433 - 22 = 531121664429 is a prime.
It is a super-2 number, since 2×5311216644332 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 531121664391 and 531121664400.
It is not an unprimeable number, because it can be changed into a prime (531121664443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13628091 + ... + 13667007.
It is an arithmetic number, because the mean of its divisors is an integer number (23768779320).
Almost surely, 2531121664433 is an apocalyptic number.
It is an amenable number.
531121664433 is a deficient number, since it is larger than the sum of its proper divisors (229479273807).
531121664433 is a wasteful number, since it uses less digits than its factorization.
531121664433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42777.
The product of its digits is 155520, while the sum is 39.
Adding to 531121664433 its reverse (334466121135), we get a palindrome (865587785568).
The spelling of 531121664433 in words is "five hundred thirty-one billion, one hundred twenty-one million, six hundred sixty-four thousand, four hundred thirty-three".
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