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531124336513 = 1245142657163
BaseRepresentation
bin1111011101010010111…
…10100011011110000001
31212202220222010211100201
413232221132203132001
532200220312232023
61043554541445201
753241520241251
oct7565136433601
91782828124321
10531124336513
11195280929161
1286b28570801
133b114434a44
141b9c6b03961
15dc382edbad
hex7ba97a3781

531124336513 has 4 divisors (see below), whose sum is σ = 531167006128. Its totient is φ = 531081666900.

The previous prime is 531124336499. The next prime is 531124336573. The reversal of 531124336513 is 315633421135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-531124336513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (531124336573) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21316131 + ... + 21341032.

It is an arithmetic number, because the mean of its divisors is an integer number (132791751532).

Almost surely, 2531124336513 is an apocalyptic number.

It is an amenable number.

531124336513 is a deficient number, since it is larger than the sum of its proper divisors (42669615).

531124336513 is a wasteful number, since it uses less digits than its factorization.

531124336513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42669614.

The product of its digits is 97200, while the sum is 37.

Adding to 531124336513 its reverse (315633421135), we get a palindrome (846757757648).

The spelling of 531124336513 in words is "five hundred thirty-one billion, one hundred twenty-four million, three hundred thirty-six thousand, five hundred thirteen".

Divisors: 1 12451 42657163 531124336513