Base | Representation |
---|---|
bin | 110001011101110000… |
… | …001111000010110011 |
3 | 12002002111121020110012 |
4 | 301131300033002303 |
5 | 1332233302030141 |
6 | 40222145525135 |
7 | 3560115040325 |
oct | 613560170263 |
9 | 162074536405 |
10 | 53112533171 |
11 | 20585705315 |
12 | a3633437ab |
13 | 5015865629 |
14 | 27dbc6b615 |
15 | 15acc66ceb |
hex | c5dc0f0b3 |
53112533171 has 2 divisors, whose sum is σ = 53112533172. Its totient is φ = 53112533170.
The previous prime is 53112533147. The next prime is 53112533209. The reversal of 53112533171 is 17133521135.
53112533171 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53112533171 - 210 = 53112532147 is a prime.
It is not a weakly prime, because it can be changed into another prime (55112533171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26556266585 + 26556266586.
It is an arithmetic number, because the mean of its divisors is an integer number (26556266586).
Almost surely, 253112533171 is an apocalyptic number.
53112533171 is a deficient number, since it is larger than the sum of its proper divisors (1).
53112533171 is an equidigital number, since it uses as much as digits as its factorization.
53112533171 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9450, while the sum is 32.
The spelling of 53112533171 in words is "fifty-three billion, one hundred twelve million, five hundred thirty-three thousand, one hundred seventy-one".
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