53114433121 has 4 divisors (see below), whose sum is σ = 53116332592. Its totient is φ = 53112533652.

The previous prime is 53114433109. The next prime is 53114433137. The reversal of 53114433121 is 12133441135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53114433121 is a prime.

It is a super-2 number, since 2×53114433121² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53114433121.

It is not an unprimeable number, because it can be changed into a prime (53114733121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 907155 + ... + 963928.

It is an arithmetic number, because the mean of its divisors is an integer number (13279083148).

Almost surely, 2^53114433121 is an apocalyptic number.

It is an amenable number.

53114433121 is a deficient number, since it is larger than the sum of its proper divisors (1899471).

53114433121 is a wasteful number, since it uses less digits than its factorization.

53114433121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1899470.

The product of its digits is 4320, while the sum is 28.

Adding to 53114433121 its reverse (12133441135), we get a palindrome (65247874256).

The spelling of 53114433121 in words is "fifty-three billion, one hundred fourteen million, four hundred thirty-three thousand, one hundred twenty-one".