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53120015545132 = 2243308837299681
BaseRepresentation
bin11000001001111111101111…
…01010000011001100101100
320222002020001012211221000001
430010333313222003030230
523430304242434421012
6304550555342314044
714121536335113544
oct1404776752031454
9228066035757001
1053120015545132
1115a20087a371a8
125b5b021888924
132384271720a33
14d19045932324
15621b908ca357
hex304ff7a8332c

53120015545132 has 12 divisors (see below), whose sum is σ = 95121888302056. Its totient is φ = 25942333173120.

The previous prime is 53120015545087. The next prime is 53120015545133. The reversal of 53120015545132 is 23154551002135.

It is a super-2 number, since 2×531200155451322 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53120015545091 and 53120015545100.

It is not an unprimeable number, because it can be changed into a prime (53120015545133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154418649669 + ... + 154418650012.

Almost surely, 253120015545132 is an apocalyptic number.

It is an amenable number.

53120015545132 is a deficient number, since it is larger than the sum of its proper divisors (42001872756924).

53120015545132 is a wasteful number, since it uses less digits than its factorization.

53120015545132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 308837299728 (or 308837299726 counting only the distinct ones).

The product of its (nonzero) digits is 90000, while the sum is 37.

Adding to 53120015545132 its reverse (23154551002135), we get a palindrome (76274566547267).

The spelling of 53120015545132 in words is "fifty-three trillion, one hundred twenty billion, fifteen million, five hundred forty-five thousand, one hundred thirty-two".

Divisors: 1 2 4 43 86 172 308837299681 617674599362 1235349198724 13280003886283 26560007772566 53120015545132