Base | Representation |
---|---|
bin | 100110101001101010011… |
… | …0100100011001100101001 |
3 | 200210211120212122100222011 |
4 | 1031103110310203030221 |
5 | 1144013240412421210 |
6 | 15144211300555521 |
7 | 1055535014013514 |
oct | 115232464431451 |
9 | 20724525570864 |
10 | 5312150123305 |
11 | 1768963291283 |
12 | 7196443b2ba1 |
13 | 2c6c1a19a73c |
14 | 145176423d7b |
15 | 932ab906d8a |
hex | 4d4d4d23329 |
5312150123305 has 32 divisors (see below), whose sum is σ = 6722278732800. Its totient is φ = 4018739380992.
The previous prime is 5312150123239. The next prime is 5312150123327. The reversal of 5312150123305 is 5033210512135.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5312150123305 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 154096611 + ... + 154131079.
It is an arithmetic number, because the mean of its divisors is an integer number (210071210400).
Almost surely, 25312150123305 is an apocalyptic number.
It is an amenable number.
5312150123305 is a deficient number, since it is larger than the sum of its proper divisors (1410128609495).
5312150123305 is a wasteful number, since it uses less digits than its factorization.
5312150123305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37393.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 5312150123305 in words is "five trillion, three hundred twelve billion, one hundred fifty million, one hundred twenty-three thousand, three hundred five".
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