Base | Representation |
---|---|
bin | 111100011001001001001001… |
… | …1101110010010001000111011 |
3 | 2120122220020210201210000101112 |
4 | 1320302102103232102020323 |
5 | 1024112012021114002024 |
6 | 5121451353442510535 |
7 | 216615315612354002 |
oct | 17062222356221073 |
9 | 2518806721700345 |
10 | 531221213422139 |
11 | 144299719082a49 |
12 | 4b6b629166544b |
13 | 19a54c3a2a9116 |
14 | 952735b43bc39 |
15 | 416343991b00e |
hex | 1e32493b9223b |
531221213422139 has 2 divisors, whose sum is σ = 531221213422140. Its totient is φ = 531221213422138.
The previous prime is 531221213422073. The next prime is 531221213422153. The reversal of 531221213422139 is 931224312122135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-531221213422139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 531221213422096 and 531221213422105.
It is not a weakly prime, because it can be changed into another prime (531221213422639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265610606711069 + 265610606711070.
It is an arithmetic number, because the mean of its divisors is an integer number (265610606711070).
Almost surely, 2531221213422139 is an apocalyptic number.
531221213422139 is a deficient number, since it is larger than the sum of its proper divisors (1).
531221213422139 is an equidigital number, since it uses as much as digits as its factorization.
531221213422139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 41.
The spelling of 531221213422139 in words is "five hundred thirty-one trillion, two hundred twenty-one billion, two hundred thirteen million, four hundred twenty-two thousand, one hundred thirty-nine".
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