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531244043531 is a prime number
BaseRepresentation
bin1111011101100001001…
…11001100110100001011
31212210020022101120111222
413232300213030310023
532200441433343111
61044014455312255
753244502602305
oct7566047146413
91783208346458
10531244043531
1119533245a883
1286b6067b68b
133b1331884b6
141b9d8984975
15dc43a977db
hex7bb09ccd0b

531244043531 has 2 divisors, whose sum is σ = 531244043532. Its totient is φ = 531244043530.

The previous prime is 531244043483. The next prime is 531244043537. The reversal of 531244043531 is 135340442135.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-531244043531 is a prime.

It is a super-2 number, since 2×5312440435312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 531244043491 and 531244043500.

It is not a weakly prime, because it can be changed into another prime (531244043537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265622021765 + 265622021766.

It is an arithmetic number, because the mean of its divisors is an integer number (265622021766).

Almost surely, 2531244043531 is an apocalyptic number.

531244043531 is a deficient number, since it is larger than the sum of its proper divisors (1).

531244043531 is an equidigital number, since it uses as much as digits as its factorization.

531244043531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 531244043531 its reverse (135340442135), we get a palindrome (666584485666).

The spelling of 531244043531 in words is "five hundred thirty-one billion, two hundred forty-four million, forty-three thousand, five hundred thirty-one".