Base | Representation |
---|---|
bin | 1111011101100001111… |
… | …01111100000001000010 |
3 | 1212210020201121101210100 |
4 | 13232300331330001002 |
5 | 32201000000112114 |
6 | 1044015231143230 |
7 | 53244604346001 |
oct | 7566075740102 |
9 | 1783221541710 |
10 | 531250004034 |
11 | 195335861012 |
12 | 86b62674b16 |
13 | 3b134494519 |
14 | 1b9d9696c38 |
15 | dc44373909 |
hex | 7bb0f7c042 |
531250004034 has 24 divisors (see below), whose sum is σ = 1151206924140. Its totient is φ = 177057911808.
The previous prime is 531250004023. The next prime is 531250004071. The reversal of 531250004034 is 430400052135.
531250004034 is a `hidden beast` number, since 5 + 3 + 1 + 250 + 0 + 0 + 403 + 4 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 530343693009 + 906311025 = 728247^2 + 30105^2 .
It is a super-2 number, since 2×5312500040342 (a number of 24 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 531250003989 and 531250004007.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1989499 + ... + 2240670.
Almost surely, 2531250004034 is an apocalyptic number.
531250004034 is an abundant number, since it is smaller than the sum of its proper divisors (619956920106).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531250004034 is a wasteful number, since it uses less digits than its factorization.
531250004034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4237154 (or 4237151 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 27.
Adding to 531250004034 its reverse (430400052135), we get a palindrome (961650056169).
The spelling of 531250004034 in words is "five hundred thirty-one billion, two hundred fifty million, four thousand, thirty-four".
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