Base | Representation |
---|---|
bin | 110001011110100000… |
… | …110000110001011001 |
3 | 12002010101112112110122 |
4 | 301132200300301121 |
5 | 1332300031113413 |
6 | 40223322323025 |
7 | 3560331132062 |
oct | 613640606131 |
9 | 162111475418 |
10 | 53125254233 |
11 | 20591903897 |
12 | a367659475 |
13 | 501839a89c |
14 | 27dd81d569 |
15 | 15ade2b108 |
hex | c5e830c59 |
53125254233 has 2 divisors, whose sum is σ = 53125254234. Its totient is φ = 53125254232.
The previous prime is 53125254199. The next prime is 53125254289. The reversal of 53125254233 is 33245252135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 51172321369 + 1952932864 = 226213^2 + 44192^2 .
It is a cyclic number.
It is not a de Polignac number, because 53125254233 - 28 = 53125253977 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53125254193 and 53125254202.
It is not a weakly prime, because it can be changed into another prime (53127254233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26562627116 + 26562627117.
It is an arithmetic number, because the mean of its divisors is an integer number (26562627117).
Almost surely, 253125254233 is an apocalyptic number.
It is an amenable number.
53125254233 is a deficient number, since it is larger than the sum of its proper divisors (1).
53125254233 is an equidigital number, since it uses as much as digits as its factorization.
53125254233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 108000, while the sum is 35.
The spelling of 53125254233 in words is "fifty-three billion, one hundred twenty-five million, two hundred fifty-four thousand, two hundred thirty-three".
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