Base | Representation |
---|---|
bin | 1111011101100010010… |
… | …11010111101101010011 |
3 | 1212210020222020022002202 |
4 | 13232301023113231103 |
5 | 32201001400302311 |
6 | 1044015434433415 |
7 | 53244646313114 |
oct | 7566113275523 |
9 | 1783228208082 |
10 | 531253525331 |
11 | 195337846681 |
12 | 86b6389286b |
13 | 3b135128229 |
14 | 1b9d9d3220b |
15 | dc4481be3b |
hex | 7bb12d7b53 |
531253525331 has 4 divisors (see below), whose sum is σ = 531255192672. Its totient is φ = 531251857992.
The previous prime is 531253525267. The next prime is 531253525343. The reversal of 531253525331 is 133525352135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 531253525331 - 26 = 531253525267 is a prime.
It is a super-2 number, since 2×5312535253312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (531253525381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190160 + ... + 1048173.
It is an arithmetic number, because the mean of its divisors is an integer number (132813798168).
Almost surely, 2531253525331 is an apocalyptic number.
531253525331 is a deficient number, since it is larger than the sum of its proper divisors (1667341).
531253525331 is a wasteful number, since it uses less digits than its factorization.
531253525331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1667340.
The product of its digits is 202500, while the sum is 38.
Adding to 531253525331 its reverse (133525352135), we get a palindrome (664778877466).
The spelling of 531253525331 in words is "five hundred thirty-one billion, two hundred fifty-three million, five hundred twenty-five thousand, three hundred thirty-one".
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