Base | Representation |
---|---|
bin | 100110101010000110110… |
… | …0000010100001111110011 |
3 | 200210221001011010000212110 |
4 | 1031110031200110033303 |
5 | 1144022212341323444 |
6 | 15144445512100403 |
7 | 1055600412242214 |
oct | 115241540241763 |
9 | 20727034100773 |
10 | 5313101120499 |
11 | 1769301085577 |
12 | 71986a994703 |
13 | 2c703c20b383 |
14 | 14522685740b |
15 | 93315158cb9 |
hex | 4d50d8143f3 |
5313101120499 has 4 divisors (see below), whose sum is σ = 7084134827336. Its totient is φ = 3542067413664.
The previous prime is 5313101120471. The next prime is 5313101120507. The reversal of 5313101120499 is 9940211013135.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5313101120499 - 231 = 5310953636851 is a prime.
It is a super-3 number, since 3×53131011204993 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5313101120449) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 885516853414 + ... + 885516853419.
It is an arithmetic number, because the mean of its divisors is an integer number (1771033706834).
Almost surely, 25313101120499 is an apocalyptic number.
5313101120499 is a deficient number, since it is larger than the sum of its proper divisors (1771033706837).
5313101120499 is a wasteful number, since it uses less digits than its factorization.
5313101120499 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1771033706836.
The product of its (nonzero) digits is 29160, while the sum is 39.
The spelling of 5313101120499 in words is "five trillion, three hundred thirteen billion, one hundred one million, one hundred twenty thousand, four hundred ninety-nine".
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