Base | Representation |
---|---|
bin | 111100011001110010100111… |
… | …0101110110001000010011101 |
3 | 2120200012202121212020200210120 |
4 | 1320303211032232301002131 |
5 | 1024114441343024442023 |
6 | 5122000320454425153 |
7 | 216624620204645625 |
oct | 17063451656610235 |
9 | 2520182555220716 |
10 | 531310250234013 |
11 | 144323459033598 |
12 | 4b70b59b9621b9 |
13 | 19a604596ac8a3 |
14 | 952b7a6451885 |
15 | 41658eb4388e3 |
hex | 1e3394ebb109d |
531310250234013 has 16 divisors (see below), whose sum is σ = 716374512296640. Its totient is φ = 350226423510656.
The previous prime is 531310250233943. The next prime is 531310250234069. The reversal of 531310250234013 is 310432052013135.
It is a cyclic number.
It is not a de Polignac number, because 531310250234013 - 212 = 531310250229917 is a prime.
It is a super-2 number, since 2×5313102502340132 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531310250234513) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 229082131 + ... + 231389807.
It is an arithmetic number, because the mean of its divisors is an integer number (44773407018540).
Almost surely, 2531310250234013 is an apocalyptic number.
It is an amenable number.
531310250234013 is a deficient number, since it is larger than the sum of its proper divisors (185064262062627).
531310250234013 is a wasteful number, since it uses less digits than its factorization.
531310250234013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3170076.
The product of its (nonzero) digits is 32400, while the sum is 33.
The spelling of 531310250234013 in words is "five hundred thirty-one trillion, three hundred ten billion, two hundred fifty million, two hundred thirty-four thousand, thirteen".
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