Base | Representation |
---|---|
bin | 11000001010010100111110… |
… | …00101110001110010100011 |
3 | 20222010022110122002001010122 |
4 | 30011022133011301302203 |
5 | 23431001114110343043 |
6 | 305000122422350455 |
7 | 14122421661030161 |
oct | 1405123705616243 |
9 | 228108418061118 |
10 | 53131414543523 |
11 | 15a249a7416428 |
12 | 5b6128328b42b |
13 | 238536a1c8ab4 |
14 | d198077c6231 |
15 | 62210b4d1368 |
hex | 30529f171ca3 |
53131414543523 has 4 divisors (see below), whose sum is σ = 53149406898168. Its totient is φ = 53113422188880.
The previous prime is 53131414543511. The next prime is 53131414543577. The reversal of 53131414543523 is 32534541413135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53131414543523 - 216 = 53131414477987 is a prime.
It is a super-2 number, since 2×531314145435232 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53131414545523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8996172893 + ... + 8996178798.
It is an arithmetic number, because the mean of its divisors is an integer number (13287351724542).
Almost surely, 253131414543523 is an apocalyptic number.
53131414543523 is a deficient number, since it is larger than the sum of its proper divisors (17992354645).
53131414543523 is a wasteful number, since it uses less digits than its factorization.
53131414543523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17992354644.
The product of its digits is 1296000, while the sum is 44.
Adding to 53131414543523 its reverse (32534541413135), we get a palindrome (85665955956658).
The spelling of 53131414543523 in words is "fifty-three trillion, one hundred thirty-one billion, four hundred fourteen million, five hundred forty-three thousand, five hundred twenty-three".
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