Base | Representation |
---|---|
bin | 1111011101101001101… |
… | …00000111111100100001 |
3 | 1212210102020001011221012 |
4 | 13232310310013330201 |
5 | 32201113010242241 |
6 | 1044025454310305 |
7 | 53246320035305 |
oct | 7566464077441 |
9 | 1783366034835 |
10 | 531314540321 |
11 | 195369230094 |
12 | 86b801b8395 |
13 | 3b14496c186 |
14 | 1ba04095d05 |
15 | dc49d706eb |
hex | 7bb4d07f21 |
531314540321 has 2 divisors, whose sum is σ = 531314540322. Its totient is φ = 531314540320.
The previous prime is 531314540311. The next prime is 531314540329. The reversal of 531314540321 is 123045413135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 309180481600 + 222134058721 = 556040^2 + 471311^2 .
It is a cyclic number.
It is not a de Polignac number, because 531314540321 - 218 = 531314278177 is a prime.
It is not a weakly prime, because it can be changed into another prime (531314540329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265657270160 + 265657270161.
It is an arithmetic number, because the mean of its divisors is an integer number (265657270161).
Almost surely, 2531314540321 is an apocalyptic number.
It is an amenable number.
531314540321 is a deficient number, since it is larger than the sum of its proper divisors (1).
531314540321 is an equidigital number, since it uses as much as digits as its factorization.
531314540321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 531314540321 its reverse (123045413135), we get a palindrome (654359953456).
The spelling of 531314540321 in words is "five hundred thirty-one billion, three hundred fourteen million, five hundred forty thousand, three hundred twenty-one".
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