Base | Representation |
---|---|
bin | 100110101010001000110… |
… | …1110000011100010100011 |
3 | 200210221020002011111100221 |
4 | 1031110101232003202203 |
5 | 1144022333442042242 |
6 | 15144500515423511 |
7 | 1055602231255141 |
oct | 115242156034243 |
9 | 20727202144327 |
10 | 5313171830947 |
11 | 1769337a91362 |
12 | 71988a5b4b97 |
13 | 2c7050a68386 |
14 | 145231dc2591 |
15 | 9331b475167 |
hex | 4d511b838a3 |
5313171830947 has 4 divisors (see below), whose sum is σ = 5313194700640. Its totient is φ = 5313148961256.
The previous prime is 5313171830909. The next prime is 5313171831017. The reversal of 5313171830947 is 7490381713135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5313171830947 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5313171830894 and 5313171830903.
It is not an unprimeable number, because it can be changed into a prime (5313171830647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11082747 + ... + 11552212.
It is an arithmetic number, because the mean of its divisors is an integer number (1328298675160).
Almost surely, 25313171830947 is an apocalyptic number.
5313171830947 is a deficient number, since it is larger than the sum of its proper divisors (22869693).
5313171830947 is a wasteful number, since it uses less digits than its factorization.
5313171830947 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22869692.
The product of its (nonzero) digits is 1905120, while the sum is 52.
The spelling of 5313171830947 in words is "five trillion, three hundred thirteen billion, one hundred seventy-one million, eight hundred thirty thousand, nine hundred forty-seven".
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