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53132147 = 291832143
BaseRepresentation
bin1100101010101…
…1101101110011
310200222101121022
43022223231303
5102100212042
65134450055
71213421135
oct312535563
9120871538
1053132147
1127a9aa72
121596392b
13b013c53
1470b1055
1549e7cd2
hex32abb73

53132147 has 4 divisors (see below), whose sum is σ = 54964320. Its totient is φ = 51299976.

The previous prime is 53132143. The next prime is 53132179. The reversal of 53132147 is 74123135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53132147 - 22 = 53132143 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53132143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 916043 + ... + 916100.

It is an arithmetic number, because the mean of its divisors is an integer number (13741080).

Almost surely, 253132147 is an apocalyptic number.

53132147 is a deficient number, since it is larger than the sum of its proper divisors (1832173).

53132147 is a wasteful number, since it uses less digits than its factorization.

53132147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1832172.

The product of its digits is 2520, while the sum is 26.

The square root of 53132147 is about 7289.1801322234. The cubic root of 53132147 is about 375.9405061860.

The spelling of 53132147 in words is "fifty-three million, one hundred thirty-two thousand, one hundred forty-seven".

Divisors: 1 29 1832143 53132147