Base | Representation |
---|---|
bin | 111100011001111001100011… |
… | …0010111010001101110011011 |
3 | 2120200021012001201012012101022 |
4 | 1320303303012113101232123 |
5 | 1024120212342403304001 |
6 | 5122011222314113055 |
7 | 216625655223645245 |
oct | 17063630627215633 |
9 | 2520235051165338 |
10 | 531325142244251 |
11 | 1443298001a7273 |
12 | 4b71245711b78b |
13 | 19a61990a48574 |
14 | 952c3ba1a5095 |
15 | 4165ebda1b11b |
hex | 1e33cc65d1b9b |
531325142244251 has 4 divisors (see below), whose sum is σ = 536290797779352. Its totient is φ = 526359486709152.
The previous prime is 531325142244241. The next prime is 531325142244301. The reversal of 531325142244251 is 152442241523135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 531325142244251 - 210 = 531325142243227 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (531325142244241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2482827767390 + ... + 2482827767603.
It is an arithmetic number, because the mean of its divisors is an integer number (134072699444838).
Almost surely, 2531325142244251 is an apocalyptic number.
531325142244251 is a deficient number, since it is larger than the sum of its proper divisors (4965655535101).
531325142244251 is a wasteful number, since it uses less digits than its factorization.
531325142244251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4965655535100.
The product of its digits is 1152000, while the sum is 44.
Adding to 531325142244251 its reverse (152442241523135), we get a palindrome (683767383767386).
The spelling of 531325142244251 in words is "five hundred thirty-one trillion, three hundred twenty-five billion, one hundred forty-two million, two hundred forty-four thousand, two hundred fifty-one".
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