5314042603 has 4 divisors (see below), whose sum is σ = 5319248368. Its totient is φ = 5308836840.

The previous prime is 5314042589. The next prime is 5314042649. The reversal of 5314042603 is 3062404135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5314042603 - 2⁵ = 5314042571 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5314042663) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2601351 + ... + 2603392.

It is an arithmetic number, because the mean of its divisors is an integer number (1329812092).

Almost surely, 2^5314042603 is an apocalyptic number.

5314042603 is a deficient number, since it is larger than the sum of its proper divisors (5205765).

5314042603 is a wasteful number, since it uses less digits than its factorization.

5314042603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5205764.

The product of its (nonzero) digits is 8640, while the sum is 28.

The square root of 5314042603 is about 72897.4800867629. The cubic root of 5314042603 is about 1745.0518839646.

Adding to 5314042603 its reverse (3062404135), we get a palindrome (8376446738).

The spelling of 5314042603 in words is "five billion, three hundred fourteen million, forty-two thousand, six hundred three".