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5314113244001 = 31171423007871
BaseRepresentation
bin100110101010100100111…
…0101010000101101100001
3200211000122200121020022002
41031111021311100231201
51144031300442302001
615145134145253345
71055634452165462
oct115251165205541
920730580536262
105314113244001
111769780429981
12719ab1934255
132c7170b01813
141452c103cd69
1593373e3246b
hex4d549d50b61

5314113244001 has 4 divisors (see below), whose sum is σ = 5485536251904. Its totient is φ = 5142690236100.

The previous prime is 5314113243991. The next prime is 5314113244031. The reversal of 5314113244001 is 1004423114135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5314113244001 - 238 = 5039235337057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5314113244031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85711503905 + ... + 85711503966.

It is an arithmetic number, because the mean of its divisors is an integer number (1371384062976).

Almost surely, 25314113244001 is an apocalyptic number.

It is an amenable number.

5314113244001 is a deficient number, since it is larger than the sum of its proper divisors (171423007903).

5314113244001 is a wasteful number, since it uses less digits than its factorization.

5314113244001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171423007902.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 5314113244001 its reverse (1004423114135), we get a palindrome (6318536358136).

The spelling of 5314113244001 in words is "five trillion, three hundred fourteen billion, one hundred thirteen million, two hundred forty-four thousand, one".

Divisors: 1 31 171423007871 5314113244001