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531415313131 is a prime number
BaseRepresentation
bin1111011101110101101…
…00100010101011101011
31212210200020122222020111
413232322310202223223
532201314310010011
61044043454235151
753251652426503
oct7567264425353
91783606588214
10531415313131
111954100aa1aa
1286ba9ab5ab7
133b15c7c3661
141ba13608a03
15dc53b29121
hex7bbad22aeb

531415313131 has 2 divisors, whose sum is σ = 531415313132. Its totient is φ = 531415313130.

The previous prime is 531415313089. The next prime is 531415313179. The reversal of 531415313131 is 131313514135.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 531415313131 - 27 = 531415313003 is a prime.

It is a super-2 number, since 2×5314153131312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 531415313093 and 531415313102.

It is not a weakly prime, because it can be changed into another prime (531415311131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265707656565 + 265707656566.

It is an arithmetic number, because the mean of its divisors is an integer number (265707656566).

Almost surely, 2531415313131 is an apocalyptic number.

531415313131 is a deficient number, since it is larger than the sum of its proper divisors (1).

531415313131 is an equidigital number, since it uses as much as digits as its factorization.

531415313131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8100, while the sum is 31.

Adding to 531415313131 its reverse (131313514135), we get a palindrome (662728827266).

The spelling of 531415313131 in words is "five hundred thirty-one billion, four hundred fifteen million, three hundred thirteen thousand, one hundred thirty-one".