53143121131 has 2 divisors, whose sum is σ = 53143121132. Its totient is φ = 53143121130.

The previous prime is 53143121123. The next prime is 53143121159. The reversal of 53143121131 is 13112134135.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53143121131 - 2³ = 53143121123 is a prime.

It is a super-2 number, since 2×53143121131² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53143121096 and 53143121105.

It is not a weakly prime, because it can be changed into another prime (53143121111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26571560565 + 26571560566.

It is an arithmetic number, because the mean of its divisors is an integer number (26571560566).

Almost surely, 2^53143121131 is an apocalyptic number.

53143121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

53143121131 is an equidigital number, since it uses as much as digits as its factorization.

53143121131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1080, while the sum is 25.

Adding to 53143121131 its reverse (13112134135), we get a palindrome (66255255266).

The spelling of 53143121131 in words is "fifty-three billion, one hundred forty-three million, one hundred twenty-one thousand, one hundred thirty-one".