Base | Representation |
---|---|
bin | 110001011111100100… |
… | …111010110101011011 |
3 | 12002011122011021101202 |
4 | 301133210322311123 |
5 | 1332314114334433 |
6 | 40225201304415 |
7 | 3560636035352 |
oct | 613744726533 |
9 | 162148137352 |
10 | 53143121243 |
11 | 205a09a7613 |
12 | a37163510b |
13 | 501bcb5194 |
14 | 2801d50999 |
15 | 15b07a9ee8 |
hex | c5f93ad5b |
53143121243 has 2 divisors, whose sum is σ = 53143121244. Its totient is φ = 53143121242.
The previous prime is 53143121219. The next prime is 53143121377. The reversal of 53143121243 is 34212134135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53143121243 - 212 = 53143117147 is a prime.
It is not a weakly prime, because it can be changed into another prime (53143121203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26571560621 + 26571560622.
It is an arithmetic number, because the mean of its divisors is an integer number (26571560622).
Almost surely, 253143121243 is an apocalyptic number.
53143121243 is a deficient number, since it is larger than the sum of its proper divisors (1).
53143121243 is an equidigital number, since it uses as much as digits as its factorization.
53143121243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8640, while the sum is 29.
Adding to 53143121243 its reverse (34212134135), we get a palindrome (87355255378).
The spelling of 53143121243 in words is "fifty-three billion, one hundred forty-three million, one hundred twenty-one thousand, two hundred forty-three".
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