Base | Representation |
---|---|
bin | 111100011011010100011110… |
… | …0101000100011101110101010 |
3 | 2120200221212001120010122021112 |
4 | 1320312220330220203232222 |
5 | 1024131412234400424000 |
6 | 5122241033441510322 |
7 | 216646040002420643 |
oct | 17066507450435652 |
9 | 2520855046118245 |
10 | 531520400014250 |
11 | 1443a4599110919 |
12 | 4b74426a6423a2 |
13 | 19a7720a73c08a |
14 | 9537a205246ca |
15 | 416b0ea9a5235 |
hex | 1e36a3ca23baa |
531520400014250 has 16 divisors (see below), whose sum is σ = 995006188827144. Its totient is φ = 212608160005600.
The previous prime is 531520400014193. The next prime is 531520400014301. The reversal of 531520400014250 is 52410004025135.
It can be written as a sum of positive squares in 4 ways, for example, as 62481800038849 + 469038599975401 = 7904543^2 + 21657299^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1063040799779 + ... + 1063040800278.
Almost surely, 2531520400014250 is an apocalyptic number.
531520400014250 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
531520400014250 is a deficient number, since it is larger than the sum of its proper divisors (463485788812894).
531520400014250 is a wasteful number, since it uses less digits than its factorization.
531520400014250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2126081600074 (or 2126081600064 counting only the distinct ones).
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 531520400014250 its reverse (52410004025135), we get a palindrome (583930404039385).
The spelling of 531520400014250 in words is "five hundred thirty-one trillion, five hundred twenty billion, four hundred million, fourteen thousand, two hundred fifty".
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