Base | Representation |
---|---|
bin | 110001100000110100… |
… | …100100100101101001 |
3 | 12002020002110002220211 |
4 | 301200310210211221 |
5 | 1332334441023031 |
6 | 40231225021121 |
7 | 3561311362222 |
oct | 614064444551 |
9 | 162202402824 |
10 | 53164001641 |
11 | 20601769343 |
12 | a3786247a1 |
13 | 502341624a |
14 | 2804a28249 |
15 | 15b2531bb1 |
hex | c60d24969 |
53164001641 has 2 divisors, whose sum is σ = 53164001642. Its totient is φ = 53164001640.
The previous prime is 53164001581. The next prime is 53164001651. The reversal of 53164001641 is 14610046135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40576059225 + 12587942416 = 201435^2 + 112196^2 .
It is a cyclic number.
It is not a de Polignac number, because 53164001641 - 223 = 53155613033 is a prime.
It is a super-2 number, since 2×531640016412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53164001651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26582000820 + 26582000821.
It is an arithmetic number, because the mean of its divisors is an integer number (26582000821).
Almost surely, 253164001641 is an apocalyptic number.
It is an amenable number.
53164001641 is a deficient number, since it is larger than the sum of its proper divisors (1).
53164001641 is an equidigital number, since it uses as much as digits as its factorization.
53164001641 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 53164001641 its reverse (14610046135), we get a palindrome (67774047776).
The spelling of 53164001641 in words is "fifty-three billion, one hundred sixty-four million, one thousand, six hundred forty-one".
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