Base | Representation |
---|---|
bin | 11000001011011000110001… |
… | …10110011100010001101011 |
3 | 20222020210102120212121010002 |
4 | 30011230120312130101223 |
5 | 23432100142133110323 |
6 | 305024542531213215 |
7 | 14125151033350643 |
oct | 1405543066342153 |
9 | 228223376777102 |
10 | 53167817081963 |
11 | 15a3938772a341 |
12 | 5b6834244720b |
13 | 238891bb7977c |
14 | d1b49c2a5523 |
15 | 62303c258828 |
hex | 305b18d9c46b |
53167817081963 has 2 divisors, whose sum is σ = 53167817081964. Its totient is φ = 53167817081962.
The previous prime is 53167817081927. The next prime is 53167817081987. The reversal of 53167817081963 is 36918071876135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53167817081963 is a prime.
It is a super-2 number, since 2×531678170819632 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 53167817081963.
It is not a weakly prime, because it can be changed into another prime (53167817081063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26583908540981 + 26583908540982.
It is an arithmetic number, because the mean of its divisors is an integer number (26583908540982).
Almost surely, 253167817081963 is an apocalyptic number.
53167817081963 is a deficient number, since it is larger than the sum of its proper divisors (1).
53167817081963 is an equidigital number, since it uses as much as digits as its factorization.
53167817081963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45722880, while the sum is 65.
The spelling of 53167817081963 in words is "fifty-three trillion, one hundred sixty-seven billion, eight hundred seventeen million, eighty-one thousand, nine hundred sixty-three".
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