Base | Representation |
---|---|
bin | 110001100001010011… |
… | …000101100000000001 |
3 | 12002020122111111122211 |
4 | 301201103011200001 |
5 | 1332344013011034 |
6 | 40232112302121 |
7 | 3561436356256 |
oct | 614123054001 |
9 | 162218444584 |
10 | 53172000769 |
11 | 20606232198 |
12 | a37b241941 |
13 | 5024c87164 |
14 | 2805b0b42d |
15 | 15b30b1d64 |
hex | c614c5801 |
53172000769 has 2 divisors, whose sum is σ = 53172000770. Its totient is φ = 53172000768.
The previous prime is 53172000757. The next prime is 53172000787. The reversal of 53172000769 is 96700027135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52392921025 + 779079744 = 228895^2 + 27912^2 .
It is a cyclic number.
It is not a de Polignac number, because 53172000769 - 215 = 53171968001 is a prime.
It is a super-2 number, since 2×531720007692 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53172000799) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26586000384 + 26586000385.
It is an arithmetic number, because the mean of its divisors is an integer number (26586000385).
Almost surely, 253172000769 is an apocalyptic number.
It is an amenable number.
53172000769 is a deficient number, since it is larger than the sum of its proper divisors (1).
53172000769 is an equidigital number, since it uses as much as digits as its factorization.
53172000769 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 79380, while the sum is 40.
The spelling of 53172000769 in words is "fifty-three billion, one hundred seventy-two million, seven hundred sixty-nine", and thus it is an aban number.
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