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53200445041 = 225312361211
BaseRepresentation
bin110001100010111111…
…100101111001110001
312002022122000121212101
4301202333211321301
51332423303220131
640235010100401
73562233215212
oct614277457161
9162278017771
1053200445041
112062029a857
12a38887a701
13502ab35ca3
1428097d3409
1515b582ec61
hexc62fe5e71

53200445041 has 4 divisors (see below), whose sum is σ = 53202828784. Its totient is φ = 53198061300.

The previous prime is 53200445033. The next prime is 53200445057. The reversal of 53200445041 is 14054400235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53200445041 - 23 = 53200445033 is a prime.

It is a super-2 number, since 2×532004450412 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53200445141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1158075 + ... + 1203136.

It is an arithmetic number, because the mean of its divisors is an integer number (13300707196).

Almost surely, 253200445041 is an apocalyptic number.

It is an amenable number.

53200445041 is a deficient number, since it is larger than the sum of its proper divisors (2383743).

53200445041 is a wasteful number, since it uses less digits than its factorization.

53200445041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2383742.

The product of its (nonzero) digits is 9600, while the sum is 28.

Adding to 53200445041 its reverse (14054400235), we get a palindrome (67254845276).

The spelling of 53200445041 in words is "fifty-three billion, two hundred million, four hundred forty-five thousand, forty-one".

Divisors: 1 22531 2361211 53200445041