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532014034 = 21511176047
BaseRepresentation
bin11111101101011…
…110001111010010
31101002002010001111
4133231132033102
52042143422114
6124442523534
716120021216
oct3755361722
91332063044
10532014034
11253343022
1212a2065aa
13862b3a06
145092a946
1531a8dbc4
hex1fb5e3d2

532014034 has 8 divisors (see below), whose sum is σ = 798553728. Its totient is φ = 265829460.

The previous prime is 532014013. The next prime is 532014037. The reversal of 532014034 is 430410235.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 532013996 and 532014014.

It is not an unprimeable number, because it can be changed into a prime (532014037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85002 + ... + 91045.

It is an arithmetic number, because the mean of its divisors is an integer number (99819216).

Almost surely, 2532014034 is an apocalyptic number.

532014034 is a deficient number, since it is larger than the sum of its proper divisors (266539694).

532014034 is a wasteful number, since it uses less digits than its factorization.

532014034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 177560.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 532014034 is about 23065.4294128681. The cubic root of 532014034 is about 810.2910268570.

Adding to 532014034 its reverse (430410235), we get a palindrome (962424269).

The spelling of 532014034 in words is "five hundred thirty-two million, fourteen thousand, thirty-four".

Divisors: 1 2 1511 3022 176047 352094 266007017 532014034