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53201413130251 = 122514342618001
BaseRepresentation
bin11000001100010111010110…
…10101001100100000001011
320222101000010221202200100211
430012023223111030200023
523433122443230132001
6305052220343141551
714130450420142411
oct1406135325144013
9228330127680324
1053201413130251
1115a51657832701
125b729597448b7
13238bb4426a099
14d1cd681512b1
15623d56913351
hex3062eb54c80b

53201413130251 has 4 divisors (see below), whose sum is σ = 53205755760504. Its totient is φ = 53197070500000.

The previous prime is 53201413130233. The next prime is 53201413130291. The reversal of 53201413130251 is 15203131410235.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53201413130251 - 213 = 53201413122059 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53201413130231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2171296750 + ... + 2171321251.

It is an arithmetic number, because the mean of its divisors is an integer number (13301438940126).

Almost surely, 253201413130251 is an apocalyptic number.

53201413130251 is a deficient number, since it is larger than the sum of its proper divisors (4342630253).

53201413130251 is a wasteful number, since it uses less digits than its factorization.

53201413130251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4342630252.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 53201413130251 its reverse (15203131410235), we get a palindrome (68404544540486).

The spelling of 53201413130251 in words is "fifty-three trillion, two hundred one billion, four hundred thirteen million, one hundred thirty thousand, two hundred fifty-one".

Divisors: 1 12251 4342618001 53201413130251