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5320226136473 = 5990173324347
BaseRepresentation
bin100110101101011011000…
…1100000110000110011001
3200211121102201002100022222
41031122312030012012121
51144131310342331343
615152024513553425
71056242110003433
oct115326614060631
920747381070288
105320226136473
111771327a57526
1271b118b75875
132c79063a6361
14145700c37653
15935d0919a68
hex4d6b6306199

5320226136473 has 4 divisors (see below), whose sum is σ = 5410399460880. Its totient is φ = 5230052812068.

The previous prime is 5320226136457. The next prime is 5320226136487. The reversal of 5320226136473 is 3746316220235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5320226136473 - 24 = 5320226136457 is a prime.

It is a super-2 number, since 2×53202261364732 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5320226133473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45086662115 + ... + 45086662232.

It is an arithmetic number, because the mean of its divisors is an integer number (1352599865220).

Almost surely, 25320226136473 is an apocalyptic number.

It is an amenable number.

5320226136473 is a deficient number, since it is larger than the sum of its proper divisors (90173324407).

5320226136473 is an equidigital number, since it uses as much as digits as its factorization.

5320226136473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 90173324406.

The product of its (nonzero) digits is 1088640, while the sum is 44.

The spelling of 5320226136473 in words is "five trillion, three hundred twenty billion, two hundred twenty-six million, one hundred thirty-six thousand, four hundred seventy-three".

Divisors: 1 59 90173324347 5320226136473