Base | Representation |
---|---|
bin | 111100011110111111100110… |
… | …0111011011000000111000100 |
3 | 2120202202010101010211020010022 |
4 | 1320331333030323120013010 |
5 | 1024213200340000241012 |
6 | 5123305021411314312 |
7 | 220030363460006450 |
oct | 17075771473300704 |
9 | 2522663333736108 |
10 | 532025332040132 |
11 | 144579749079367 |
12 | 4b8060a72ab998 |
13 | 19ab2a09609058 |
14 | 9554240793660 |
15 | 41792ee5b4472 |
hex | 1e3dfcced81c4 |
532025332040132 has 24 divisors (see below), whose sum is σ = 1064825646432576. Its totient is φ = 227844788941728.
The previous prime is 532025332040087. The next prime is 532025332040143. The reversal of 532025332040132 is 231040233520235.
It is a junction number, because it is equal to n+sod(n) for n = 532025332040092 and 532025332040101.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6919446158 + ... + 6919523045.
It is an arithmetic number, because the mean of its divisors is an integer number (44367735268024).
Almost surely, 2532025332040132 is an apocalyptic number.
It is an amenable number.
532025332040132 is an abundant number, since it is smaller than the sum of its proper divisors (532800314392444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
532025332040132 is a wasteful number, since it uses less digits than its factorization.
532025332040132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13838970587 (or 13838970585 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 532025332040132 its reverse (231040233520235), we get a palindrome (763065565560367).
The spelling of 532025332040132 in words is "five hundred thirty-two trillion, twenty-five billion, three hundred thirty-two million, forty thousand, one hundred thirty-two".
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