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53208498617 is a prime number
BaseRepresentation
bin110001100011011110…
…010100000110111001
312002100012011210021222
4301203132110012321
51332432333423432
640235454441425
73562361530061
oct614336240671
9162305153258
1053208498617
11206248a05aa
12a38b503275
13502c6c5911
14280a8cc3a1
1515b63c1112
hexc637941b9

53208498617 has 2 divisors, whose sum is σ = 53208498618. Its totient is φ = 53208498616.

The previous prime is 53208498559. The next prime is 53208498649. The reversal of 53208498617 is 71689480235.

53208498617 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32247539776 + 20960958841 = 179576^2 + 144779^2 .

It is a cyclic number.

It is not a de Polignac number, because 53208498617 - 226 = 53141389753 is a prime.

It is a super-3 number, since 3×532084986173 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (53208494617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26604249308 + 26604249309.

It is an arithmetic number, because the mean of its divisors is an integer number (26604249309).

It is a 1-persistent number, because it is pandigital, but 2⋅53208498617 = 106416997234 is not.

Almost surely, 253208498617 is an apocalyptic number.

It is an amenable number.

53208498617 is a deficient number, since it is larger than the sum of its proper divisors (1).

53208498617 is an equidigital number, since it uses as much as digits as its factorization.

53208498617 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 53208498617 in words is "fifty-three billion, two hundred eight million, four hundred ninety-eight thousand, six hundred seventeen".