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532242242234 = 2266121121117
BaseRepresentation
bin1111011111011000001…
…11000001101010111010
31212212210212200022201022
413233230013001222322
532210013003222414
61044301514222442
753311313261513
oct7575407015272
91785725608638
10532242242234
111957a496328a
128719aa24a22
133b261c14811
141ba91383a0a
15dca152018e
hex7bec1c1aba

532242242234 has 4 divisors (see below), whose sum is σ = 798363363354. Its totient is φ = 266121121116.

The previous prime is 532242242201. The next prime is 532242242261. The reversal of 532242242234 is 432242242235.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 504388301209 + 27853941025 = 710203^2 + 166895^2 .

It is a junction number, because it is equal to n+sod(n) for n = 532242242194 and 532242242203.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 133060560557 + ... + 133060560560.

Almost surely, 2532242242234 is an apocalyptic number.

532242242234 is a deficient number, since it is larger than the sum of its proper divisors (266121121120).

532242242234 is a wasteful number, since it uses less digits than its factorization.

532242242234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 266121121119.

The product of its digits is 184320, while the sum is 35.

Adding to 532242242234 its reverse (432242242235), we get a palindrome (964484484469).

Subtracting from 532242242234 its reverse (432242242235), we obtain a palindrome (99999999999).

The spelling of 532242242234 in words is "five hundred thirty-two billion, two hundred forty-two million, two hundred forty-two thousand, two hundred thirty-four".

Divisors: 1 2 266121121117 532242242234