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5322431152003 = 7760347307429
BaseRepresentation
bin100110101110011100110…
…0111100011111110000011
3200211211010101012201222211
41031130321213203332003
51144200314333331003
615153031403042551
71056350543222230
oct115347147437603
920754111181884
105322431152003
1117722596a2309
1271b633510457
132c7b98172884
1414586da1c787
15936ae2c796d
hex4d7399e3f83

5322431152003 has 4 divisors (see below), whose sum is σ = 6082778459440. Its totient is φ = 4562083844568.

The previous prime is 5322431151997. The next prime is 5322431152037. The reversal of 5322431152003 is 3002511342235.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5322431152003 - 25 = 5322431151971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5322431132003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380173653708 + ... + 380173653721.

It is an arithmetic number, because the mean of its divisors is an integer number (1520694614860).

Almost surely, 25322431152003 is an apocalyptic number.

5322431152003 is a deficient number, since it is larger than the sum of its proper divisors (760347307437).

5322431152003 is an equidigital number, since it uses as much as digits as its factorization.

5322431152003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 760347307436.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 5322431152003 its reverse (3002511342235), we get a palindrome (8324942494238).

The spelling of 5322431152003 in words is "five trillion, three hundred twenty-two billion, four hundred thirty-one million, one hundred fifty-two thousand, three".

Divisors: 1 7 760347307429 5322431152003