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53225143123 = 187043284561
BaseRepresentation
bin110001100100011101…
…110011101101010011
312002101100111102021011
4301210131303231103
51333001114034443
640241251311351
73562653152245
oct614435635523
9162340442234
1053225143123
1120633229899
12a394bab557
135032ca2939
14280cbc2095
1515b7aacb9d
hexc64773b53

53225143123 has 4 divisors (see below), whose sum is σ = 53225614728. Its totient is φ = 53224671520.

The previous prime is 53225143117. The next prime is 53225143129. The reversal of 53225143123 is 32134152235.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is an interprime number because it is at equal distance from previous prime (53225143117) and next prime (53225143129).

It is a cyclic number.

It is not a de Polignac number, because 53225143123 - 217 = 53225012051 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53225143129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44763 + ... + 329323.

It is an arithmetic number, because the mean of its divisors is an integer number (13306403682).

Almost surely, 253225143123 is an apocalyptic number.

53225143123 is a deficient number, since it is larger than the sum of its proper divisors (471605).

53225143123 is a wasteful number, since it uses less digits than its factorization.

53225143123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 471604.

The product of its digits is 21600, while the sum is 31.

Adding to 53225143123 its reverse (32134152235), we get a palindrome (85359295358).

The spelling of 53225143123 in words is "fifty-three billion, two hundred twenty-five million, one hundred forty-three thousand, one hundred twenty-three".

Divisors: 1 187043 284561 53225143123