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5323031141132 = 223179753861569
BaseRepresentation
bin100110101110101110101…
…1000010101101100001100
3200211212200012012100100102
41031131131120111230030
51144203031433004012
615153211114550232
71056401450104535
oct115353530255414
920755605170312
105323031141132
111772537342aa1
1271b780438378
132c7c62566523
141458c95a168c
15936e6ce22c2
hex4d75d615b0c

5323031141132 has 24 divisors (see below), whose sum is σ = 9627863360640. Its totient is φ = 2572428487680.

The previous prime is 5323031141123. The next prime is 5323031141189. The reversal of 5323031141132 is 2311411303235.

It is a super-2 number, since 2×53230311411322 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5323031141095 and 5323031141104.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26831957 + ... + 27029612.

It is an arithmetic number, because the mean of its divisors is an integer number (401160973360).

Almost surely, 25323031141132 is an apocalyptic number.

It is an amenable number.

5323031141132 is a deficient number, since it is larger than the sum of its proper divisors (4304832219508).

5323031141132 is a wasteful number, since it uses less digits than its factorization.

5323031141132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53862401 (or 53862399 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 5323031141132 its reverse (2311411303235), we get a palindrome (7634442444367).

The spelling of 5323031141132 in words is "five trillion, three hundred twenty-three billion, thirty-one million, one hundred forty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 31 62 124 797 1594 3188 24707 49414 98828 53861569 107723138 215446276 1669708639 3339417278 6678834556 42927670493 85855340986 171710681972 1330757785283 2661515570566 5323031141132