Base | Representation |
---|---|
bin | 1111011111101100100… |
… | …01000111100101001111 |
3 | 1212220020202100110000011 |
4 | 13233312101013211033 |
5 | 32210340120110142 |
6 | 1044330443014051 |
7 | 53315452640452 |
oct | 7576621074517 |
9 | 1786222313004 |
10 | 532412660047 |
11 | 195882080754 |
12 | 87227b0a327 |
13 | 3b28b312068 |
14 | 1baa9c65499 |
15 | dcb1484417 |
hex | 7bf644794f |
532412660047 has 16 divisors (see below), whose sum is σ = 568585543680. Its totient is φ = 497430108000.
The previous prime is 532412660023. The next prime is 532412660051. The reversal of 532412660047 is 740066214235.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-532412660047 is a prime.
It is a super-3 number, since 3×5324126600473 (a number of 36 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 532412659991 and 532412660009.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (532412660147) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19630498 + ... + 19657600.
It is an arithmetic number, because the mean of its divisors is an integer number (35536596480).
Almost surely, 2532412660047 is an apocalyptic number.
532412660047 is a deficient number, since it is larger than the sum of its proper divisors (36172883633).
532412660047 is a wasteful number, since it uses less digits than its factorization.
532412660047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49014.
The product of its (nonzero) digits is 241920, while the sum is 40.
The spelling of 532412660047 in words is "five hundred thirty-two billion, four hundred twelve million, six hundred sixty thousand, forty-seven".
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