Base | Representation |
---|---|
bin | 111100100010011100101110… |
… | …1111011011001011000101010 |
3 | 2120211102112010021122012120001 |
4 | 1321010321131323121120222 |
5 | 1024243440413023103414 |
6 | 5124311115254453214 |
7 | 220106604432542434 |
oct | 17104713573313052 |
9 | 2524375107565501 |
10 | 532500211144234 |
11 | 144742086a36973 |
12 | 4b88213736420a |
13 | 19b18729171988 |
14 | 956d20d55d654 |
15 | 4186844ae4074 |
hex | 1e44e5ded962a |
532500211144234 has 8 divisors (see below), whose sum is σ = 799170490481508. Its totient is φ = 266110047650400.
The previous prime is 532500211144229. The next prime is 532500211144243. The reversal of 532500211144234 is 432441112005235.
It can be written as a sum of positive squares in 2 ways, for example, as 523030725118225 + 9469486026009 = 22869865^2 + 3077253^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 532500211144193 and 532500211144202.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70028956107 + ... + 70028963710.
Almost surely, 2532500211144234 is an apocalyptic number.
532500211144234 is a deficient number, since it is larger than the sum of its proper divisors (266670279337274).
532500211144234 is a wasteful number, since it uses less digits than its factorization.
532500211144234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 140057921720.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 532500211144234 its reverse (432441112005235), we get a palindrome (964941323149469).
The spelling of 532500211144234 in words is "five hundred thirty-two trillion, five hundred billion, two hundred eleven million, one hundred forty-four thousand, two hundred thirty-four".
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