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532500211144234 = 21901140057919817
BaseRepresentation
bin111100100010011100101110…
…1111011011001011000101010
32120211102112010021122012120001
41321010321131323121120222
51024243440413023103414
65124311115254453214
7220106604432542434
oct17104713573313052
92524375107565501
10532500211144234
11144742086a36973
124b88213736420a
1319b18729171988
14956d20d55d654
154186844ae4074
hex1e44e5ded962a

532500211144234 has 8 divisors (see below), whose sum is σ = 799170490481508. Its totient is φ = 266110047650400.

The previous prime is 532500211144229. The next prime is 532500211144243. The reversal of 532500211144234 is 432441112005235.

It can be written as a sum of positive squares in 2 ways, for example, as 523030725118225 + 9469486026009 = 22869865^2 + 3077253^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 532500211144193 and 532500211144202.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70028956107 + ... + 70028963710.

Almost surely, 2532500211144234 is an apocalyptic number.

532500211144234 is a deficient number, since it is larger than the sum of its proper divisors (266670279337274).

532500211144234 is a wasteful number, since it uses less digits than its factorization.

532500211144234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 140057921720.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 532500211144234 its reverse (432441112005235), we get a palindrome (964941323149469).

The spelling of 532500211144234 in words is "five hundred thirty-two trillion, five hundred billion, two hundred eleven million, one hundred forty-four thousand, two hundred thirty-four".

Divisors: 1 2 1901 3802 140057919817 280115839634 266250105572117 532500211144234