Base | Representation |
---|---|
bin | 1111011111111000101… |
… | …00001000011001001001 |
3 | 1212220111211020210102112 |
4 | 13233330110020121021 |
5 | 32211042103104342 |
6 | 1044344505312105 |
7 | 53321124164111 |
oct | 7577424103111 |
9 | 1786454223375 |
10 | 532514113097 |
11 | 19592437494a |
12 | 87255a95635 |
13 | 3b2a6344055 |
14 | 1bab9514041 |
15 | dcba324682 |
hex | 7bfc508649 |
532514113097 has 2 divisors, whose sum is σ = 532514113098. Its totient is φ = 532514113096.
The previous prime is 532514113093. The next prime is 532514113129. The reversal of 532514113097 is 790311415235.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 508517314816 + 23996798281 = 713104^2 + 154909^2 .
It is a cyclic number.
It is not a de Polignac number, because 532514113097 - 22 = 532514113093 is a prime.
It is not a weakly prime, because it can be changed into another prime (532514113093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266257056548 + 266257056549.
It is an arithmetic number, because the mean of its divisors is an integer number (266257056549).
Almost surely, 2532514113097 is an apocalyptic number.
It is an amenable number.
532514113097 is a deficient number, since it is larger than the sum of its proper divisors (1).
532514113097 is an equidigital number, since it uses as much as digits as its factorization.
532514113097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 41.
The spelling of 532514113097 in words is "five hundred thirty-two billion, five hundred fourteen million, one hundred thirteen thousand, ninety-seven".
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