Base | Representation |
---|---|
bin | 11000001101110110001100… |
… | …11101110101000111101011 |
3 | 20222112212120201211021221222 |
4 | 30012323012131311013223 |
5 | 23434441240031304311 |
6 | 305131441251252255 |
7 | 14134232325363065 |
oct | 1406730635650753 |
9 | 228485521737858 |
10 | 53252334244331 |
11 | 15a71208439362 |
12 | 5b807aabaa08b |
13 | 239389aab6a11 |
14 | d215d8d36735 |
15 | 6253370a5adb |
hex | 306ec67751eb |
53252334244331 has 4 divisors (see below), whose sum is σ = 53281739179464. Its totient is φ = 53222929309200.
The previous prime is 53252334244321. The next prime is 53252334244337. The reversal of 53252334244331 is 13344243325235.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53252334244331 - 218 = 53252333982187 is a prime.
It is a super-2 number, since 2×532523342443312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53252334244337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14702464850 + ... + 14702468471.
It is an arithmetic number, because the mean of its divisors is an integer number (13320434794866).
Almost surely, 253252334244331 is an apocalyptic number.
53252334244331 is a deficient number, since it is larger than the sum of its proper divisors (29404935133).
53252334244331 is a wasteful number, since it uses less digits than its factorization.
53252334244331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29404935132.
The product of its digits is 3110400, while the sum is 44.
Adding to 53252334244331 its reverse (13344243325235), we get a palindrome (66596577569566).
The spelling of 53252334244331 in words is "fifty-three trillion, two hundred fifty-two billion, three hundred thirty-four million, two hundred forty-four thousand, three hundred thirty-one".
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